0=3p^2-10p-8

Solution for 0=3p^2-10p-8 equation:

0=3p^2-10p-8

We move all terms to the left:

0-(3p^2-10p-8)=0

We add all the numbers together, and all the variables

-(3p^2-10p-8)=0

We get rid of parentheses

-3p^2+10p+8=0

a = -3; b = 10; c = +8;
Δ = b2-4ac
Δ = 102-4·(-3)·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*-3}=\frac{-24}{-6}
=+4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*-3}=\frac{4}{-6}
=-2/3
$